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http://solvemaths.in/competitive5/AlgebraArithmetic11-12th,Graduate,UndergraduateRajni Sahsah.rajni@yahoo.comAdministratorSOLVE - ΜΔΓΗŠ
Answer is c) 15

There are 22 numbers between 1 and 200 divisible by 9. All numbers divisible by 9 are also divisible by 3. Multiples of 9 can also be multiples of 27. For the ‘excactly 2’ condition to be satisfied, the multiples of 27 should be excluded. There are 7 multiples of 27.

Thus reqd number is : 22-7 = 15

b) 16