# contest Question-2

In the figure shown below ABC is a triangle with BC=5 and triangle EDC has an angle ∠EDC=(90-x) degrees. If AB = 10, what is the length of the side CD ?

(A) 5

(B) [pmath size=4]5 sqrt{3}[/pmath]
(C) [pmath size=4]10/ sqrt{3}[/pmath]
(D) 10

(E) [pmath size=4]10 sqrt{3}[/pmath]

In the figure shown below ABC is a triangle with BC=5 and triangle EDC has an angle ∠EDC=(90-x) degrees. If AB = 10, what is the length of the side CD ?
(A) 5
(B) 5 sqrt{3}
(C) 10/ sqrt{3}
(D) 10
(E) 10 sqrt{3}

rammsah30@a2plcpnl0464.prod.iad2.secureserver.netAdministratorSOLVE - ΜΔΓΗŠ
C

C

C. 10/√3

A

c)10/root(3)

c

10/sqrt3

c

a)5

(A) 5

option : c

contest question 2

angle DCE=x degrees

AB^2=BC^2+AC^2

length of AC=10^2-5^2

AC=sqrt(75)

AC=5sqrt(3)

hence answer cannot be option b,d or e

by inspection option c) 10/sqrt3

c

(C)